JEE Main 2014 · 19 Apr · Shift 1 · Chemistry Q51

← JEE Main 2014 · 19 Apr · Shift 1

ChemistrySingle correct+4 / -1Question 51 of 90

The major product formed when 1, 1, 1 − trichloro - propane is treated with aqueous potassium hydroxide is :

Propyne

1 - Propanol

2 - Propanol

Propionic acid

Answer and worked solution

Official answer: D

Aqueous KOH replaces the three Cl on C1 by OH. The gem-triol $\ce{CH3CH2C(OH)3}$ loses water to give propionic acid, $\ce{CH3CH2COOH}$ (as its salt).

Topics:Polyhalogen compounds Carboxylic acids

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JEE Main 2014 · 19 Apr · Shift 1, Chemistry question 51