JEE Main 2014 · 12 Apr · Shift 1 · Physics Q25

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In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å, then wavelength of first maximum will be :

3300 Å

4400 Å

5500 Å

6600 Å

Answer and worked solution

Official answer: B

First minimum: $a\sin\theta=\lambda_r$ . First secondary maximum: $a\sin\theta\approx\frac32\lambda$ . Equating:
$\lambda=\frac23\times6600=4400\text{ Å}.$

Topics:Diffraction

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JEE Main 2014 · 12 Apr · Shift 1, Physics question 25