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← JEE Main 2014 · 12 Apr · Shift 1
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JEE Main 2014 · 12 Apr · Shift 1, Physics question 15

A source of sound A emitting waves of frequency 1800 Hz is falling towards ground with a terminal speed vv. The observer B on the ground directly beneath the source receives waves of frequency 2150 Hz. The source A receives waves, reflected from ground, of frequency nearly : (Speed of sound = 343 m/s)

Choose one option
Answer and worked solution

Official answer: B

Source approaching B: 2150=1800343343−v2150=1800\dfrac{343}{343-v}, so v≈55.8v\approx55.8 m/s.

The ground reflects 2150 Hz, and the source moves towards it as an observer:
f=2150⋅343+55.8343≈2500 Hz.f=2150\cdot\frac{343+55.8}{343}\approx2500\text{ Hz}.