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← JEE Main 2014 · 12 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 84 of 90

JEE Main 2014 · 12 Apr · Shift 1, Mathematics question 84

If the distance between planes, 4x−2y−4z+1=04x-2y-4z+1=0 and 4x−2y−4z+d=04x-2y-4z+d=0 is 7, then d is :

Choose one option
Answer and worked solution

Official answer: C

∣d−1∣16+4+16=7  ⟹  ∣d−1∣=42  ⟹  d=43 or −41.\frac{|d-1|}{\sqrt{16+4+16}}=7\implies|d-1|=42\implies d=43\text{ or }-41.

Topics:Angles and distances
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