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← JEE Main 2014 · 12 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 69 of 90

JEE Main 2014 · 12 Apr · Shift 1, Mathematics question 69

The least positive integer n such that 1−23−232−⋯−23n−1<11001-\dfrac23-\dfrac2{3^2}-\dots-\dfrac2{3^{n-1}}<\dfrac1{100}, is :

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Answer and worked solution

Official answer: C

1−2(13+⋯+13n−1)=1−(1−13n−1)=13n−11-2\left(\frac13+\dots+\frac1{3^{n-1}}\right)=1-\left(1-\frac1{3^{n-1}}\right)=\frac1{3^{n-1}}.

3n−1>1003^{n-1}>100 first holds at n−1=5n-1=5, so n=6n=6.