JEE Main 2014 · 12 Apr · Shift 1 · Chemistry Q47

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ChemistrySingle correct+4 / -1Question 47 of 90

Which of the following arrangements represents the increasing order (smallest to largest) of ionic radii of the given species $\ce{O^2-}$ , $\ce{S^2-}$ , $\ce{N^3-}$ , $\ce{P^3-}$ ?

\ce{O^2-} < \ce{N^3-} < \ce{S^2-} < \ce{P^3-}

\ce{O^2-} < \ce{P^3-} < \ce{N^3-} < \ce{S^2-}

\ce{N^3-} < \ce{O^2-} < \ce{P^3-} < \ce{S^2-}

\ce{N^3-} < \ce{S^2-} < \ce{O^2-} < \ce{P^3-}

Answer and worked solution

Official answer: A

Second-period ions are smaller than third-period ones, and for an isoelectronic pair the higher charge is larger:
$\ce{O^2-} (140) < \ce{N^3-} (171) < \ce{S^2-} (184) < \ce{P^3-} (212)\text{ pm}.$

Topics:Atomic and ionic radii

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JEE Main 2014 · 12 Apr · Shift 1, Chemistry question 47