JEE Main 2014 · 12 Apr · Shift 1 · Chemistry Q42

ChemistrySingle correct+4 / -1Question 42 of 90

Excited hydrogen atom emits light in the ultraviolet region at $2.47\times10^{15}$ Hz. With this frequency, the energy of a single photon is :

( $h=6.63\times10^{-34}$ Js)

8.041\times10^{-40}

2.680\times10^{-19}

1.640\times10^{-18}

6.111\times10^{-17}

Answer and worked solution

Official answer: C

$E=h\nu=6.63\times10^{-34}\times2.47\times10^{15}\approx1.640\times10^{-18}\text{ J}.$

JEE Main 2014 · 12 Apr · Shift 1, Chemistry question 42