JEE Main 2014 · 12 Apr · Shift 1 · Chemistry Q32

ChemistrySingle correct+4 / -1Question 32 of 90

The de-Broglie wavelength of a particle of mass 6.63 g moving with a velocity of 100 ms $^{-1}$ is :

10^{-33}

10^{-35}

10^{-31}

10^{-25}

Answer and worked solution

Official answer: A

$\lambda=\frac h{mv}=\frac{6.63\times10^{-34}}{6.63\times10^{-3}\times100}=10^{-33}\text{ m}.$

JEE Main 2014 · 12 Apr · Shift 1, Chemistry question 32