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← JEE Main 2014 · 11 Apr · Shift 1
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JEE Main 2014 · 11 Apr · Shift 1, Physics question 28

A Zener diode is connected to a battery and a load as shown below :

The currents I, IZI_Z and ILI_L are respectively

A 60 V battery drives current I through a 4 kΩ resistor to node A. From A, a Zener diode (V_Z = 10 V, current I_Z) goes down to B, and the load R_L = 2 kΩ (current I_L) is in parallel with the Zener.
Choose one option
Answer and worked solution

Official answer: D

The Zener holds the load at 10 V:

  • IL=102000=5I_L=\dfrac{10}{2000}=5 mA;
  • I=60−104000=12.5I=\dfrac{60-10}{4000}=12.5 mA;
  • IZ=12.5−5=7.5I_Z=12.5-5=7.5 mA.