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JEE Main 2014 · 11 Apr · Shift 1, Physics question 21

A coil of circular cross-section having 1000 turns and 4 cm2^2 face area is placed with its axis parallel to a magnetic field which decreases by 10−210^{-2} Wb m−2^{-2} in 0.01 s. The e.m.f. induced in the coil is :

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Answer and worked solution

Official answer: A

ε=NAdBdt=1000×4×10−4×10−20.01=0.4 V=400 mV.\varepsilon=NA\frac{dB}{dt}=1000\times4\times10^{-4}\times\frac{10^{-2}}{0.01}=0.4\text{ V}=400\text{ mV}.

Topics:Faraday's and Lenz's laws
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