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← JEE Main 2014 · 11 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 88 of 90

JEE Main 2014 · 11 Apr · Shift 1, Mathematics question 88

If 2cos⁡θ+sin⁡θ=12\cos\theta+\sin\theta=1 (θ≠π2)\left(\theta\ne\dfrac\pi2\right), then 7cos⁡θ+6sin⁡θ7\cos\theta+6\sin\theta is equal to :

Choose one option
Answer and worked solution

Official answer: B

sin⁡θ=1−2cos⁡θ\sin\theta=1-2\cos\theta, and squaring gives 5cos⁡2θ=4cos⁡θ5\cos^2\theta=4\cos\theta. So cos⁡θ=45\cos\theta=\frac45 (cos⁡θ=0\cos\theta=0 is excluded), and sin⁡θ=−35\sin\theta=-\frac35.
7cos⁡θ+6sin⁡θ=28−185=2.7\cos\theta+6\sin\theta=\frac{28-18}5=2.