JEE Main 2014 · 11 Apr · Shift 1 · Mathematics Q84

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MathematicsSingle correct+4 / -1Question 84 of 90

The plane containing the line $\dfrac{x-1}1=\dfrac{y-2}2=\dfrac{z-3}3$ and parallel to the line $\dfrac x1=\dfrac y1=\dfrac z4$ passes through the point :

(1,-2,5)

(1,0,5)

(0,3,-5)

(-1,-3,0)

Answer and worked solution

Official answer: B

Normal: $(1,2,3)\times(1,1,4)=(5,-1,-1)$ . The plane through $(1,2,3)$ is $5x-y-z=0$ , which contains $(1,0,5)$ .

Topics:Equation of a plane Cross product

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JEE Main 2014 · 11 Apr · Shift 1, Mathematics question 84