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← JEE Main 2014 · 11 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 66 of 90

JEE Main 2014 · 11 Apr · Shift 1, Mathematics question 66

An eight digit number divisible by 9 is to be formed using digits from 0 to 9 without repeating the digits. The number of ways in which this can be done is :

Choose one option
Answer and worked solution

Official answer: D

The digits 0-9 sum to 45. An 8-digit selection is divisible by 9 exactly when the two omitted digits sum to 9: {0,9},{1,8},{2,7},{3,6},{4,5}\{0,9\},\{1,8\},\{2,7\},\{3,6\},\{4,5\}.

  • Omit {0,9}\{0,9\}: digits 1-8, giving 8!8! numbers.
  • Each of the other four pairs leaves 0 in, giving 8!−7!=7⋅7!8!-7!=7\cdot7! numbers.

Total: 8⋅7!+4⋅7⋅7!=36 (7!)8\cdot7!+4\cdot7\cdot7!=36\,(7!).