JEE Main 2014 · 11 Apr · Shift 1 · Chemistry Q60

ChemistrySingle correct+4 / -1Question 60 of 90

The gas liberated by the electrolysis of Dipotassium succinate solution is :

Ethane

Ethyne

Ethene

Propene

Answer and worked solution

Official answer: C

Kolbe electrolysis of succinate, $\ce{^-OOC-CH2CH2-COO^-}$ , loses two $\ce{CO2}$ and forms a C=C bond. It gives ethene at the anode.

JEE Main 2014 · 11 Apr · Shift 1, Chemistry question 60