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← JEE Main 2014 · 11 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 54 of 90

JEE Main 2014 · 11 Apr · Shift 1, Chemistry question 54

An organic compound A, CX5HX8O\ce{C5H8O}; reacts with HX2O\ce{H2O}, NHX3\ce{NH3} and CHX3COOH\ce{CH3COOH} as described below :

  • with HX2O\ce{H2O}: ∼CH−C(=O)−OH\sim\ce{CH-C(=O)-OH}
  • with NHX3\ce{NH3}: ∼CH−C(=O)−NHX2\sim\ce{CH-C(=O)-NH2}
  • with CHX3COOH\ce{CH3COOH}: ∼CH−C(=O)−O−C(=O)−CHX3\sim\ce{CH-C(=O)-O-C(=O)-CH3}

A is :

A reacts with H₂O to give a carboxylic acid (~CH-COOH), with NH₃ to give an amide (~CH-CONH₂) and with CH₃COOH to give a mixed anhydride (~CH-CO-O-CO-CH₃).
Choose one option
Answer and worked solution

Official answer: C

Adding HX2O\ce{H2O}, NHX3\ce{NH3} and CHX3COOH\ce{CH3COOH} across a C=C=O unit gives an acid, an amide and an anhydride. That is ketene behaviour.

For CX5HX8O\ce{C5H8O}, A is ethylmethylketene, CHX3CHX2C(CHX3)=C=O\ce{CH3CH2C(CH3)=C=O}.