JEE Main 2014 · 11 Apr · Shift 1 · Chemistry Q51

ChemistrySingle correct+4 / -1Question 51 of 90

The following reaction
$\ce{C6H5OH + HCl + HCN ->[Anhyd. ZnCl2]}\ \text{2-hydroxybenzaldehyde (salicylaldehyde)}$
is known as :

Perkin reaction

Gattermann-Koch Formylation

Kolbe's reaction

Gattermann reaction

Answer and worked solution

Official answer: D

Formylating a phenol with HCN and HCl over anhydrous $\ce{ZnCl2}$ is the Gattermann reaction. Gattermann-Koch uses CO/HCl.

JEE Main 2014 · 11 Apr · Shift 1, Chemistry question 51