JEE Main 2014 · 11 Apr · Shift 1 · Chemistry Q42

ChemistrySingle correct+4 / -1Question 42 of 90

The correct order of bond dissociation energy among $\ce{N2}$ , $\ce{O2}$ , $\ce{O2-}$ is shown in which of the following arrangements ?

\ce{N2 > O2- > O2}

\ce{O2- > O2 > N2}

\ce{N2 > O2 > O2-}

\ce{O2 > O2- > N2}

Answer and worked solution

Official answer: C

Bond orders: $\ce{N2}$ 3, $\ce{O2}$ 2, $\ce{O2-}$ 1.5. A higher bond order means a stronger bond: $\ce{N2 > O2 > O2-}$ .

JEE Main 2014 · 11 Apr · Shift 1, Chemistry question 42