JEE Main 2014 · 9 Apr · Shift 1 · Physics Q17 · Dronacharya Exams

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PhysicsSingle correct+4 / -1Question 17 of 90

Three capacitances, each of 3 μF, are provided. These cannot be combined to provide the resultant capacitance of :

A

1 μF

B

2 μF

C

4.5 μF

D

6 μF

Answer and worked solution

Official answer: D

Using all three 3 μF capacitors:

all in series: 1 μF;
all in parallel: 9 μF;
two in parallel, then in series with the third: $\frac{6\cdot3}{9}=2$ μF;
two in series, then in parallel with the third: $1.5+3=4.5$ μF.

6 μF cannot be obtained.

Topics:Series and parallel combinations

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