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← JEE Main 2014 · 9 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 63 of 90

JEE Main 2014 · 9 Apr · Shift 1, Mathematics question 63

If equations ax2+bx+c=0ax^2+bx+c=0, (a,b,c∈Ra,b,c\in\mathbf R, a≠0a\ne0) and 2x2+3x+4=02x^2+3x+4=0 have a common root, then a:b:ca:b:c equals :

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Answer and worked solution

Official answer: B

2x2+3x+4=02x^2+3x+4=0 has discriminant 9−32<09-32<0, so its roots are a non-real conjugate pair. A real-coefficient quadratic sharing one of them shares both, so the two equations are proportional: a:b:c=2:3:4a:b:c=2:3:4.