JEE Main 2014 · 9 Apr · Shift 1 · Chemistry Q43

ChemistrySingle correct+4 / -1Question 43 of 90

Chloro compound of Vanadium has only spin magnetic moment of 1.73 BM. This Vanadium chloride has the formula : (at. no. of V = 23)

\ce{VCl2}

\ce{VCl4}

\ce{VCl3}

\ce{VCl5}

Answer and worked solution

Official answer: B

$\mu=\sqrt{n(n+2)}=1.73$ BM means $n=1$ unpaired electron, i.e. $\ce{V^4+}$ ( $3d^1$ ). The chloride is $\ce{VCl4}$ .

JEE Main 2014 · 9 Apr · Shift 1, Chemistry question 43