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← JEE Main 2014 · 9 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 39 of 90

JEE Main 2014 · 9 Apr · Shift 1, Chemistry question 39

The temperature at which oxygen molecules have the same root mean square speed as helium atoms have at 300 K is : (Atomic masses : He = 4 u, O = 16 u)

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Answer and worked solution

Official answer: D

vrms∝T/Mv_{\text{rms}}\propto\sqrt{T/M}:
T32=3004  ⟹  T=2400 K.\frac{T}{32}=\frac{300}4\implies T=2400\text{ K}.