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← JEE Main 2014 · 9 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 35 of 90

JEE Main 2014 · 9 Apr · Shift 1, Chemistry question 35

Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is :

Choose one option
Answer and worked solution

Official answer: B

  • Moles: 12060=2\frac{120}{60}=2.
  • Solution mass: 1120 g, so the volume is 11201.12=1000\frac{1120}{1.12}=1000 mL.

Molarity = 2.00 M.