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← JEE Main 2014 · 9 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 31 of 90

JEE Main 2014 · 9 Apr · Shift 1, Chemistry question 31

In a face centered cubic lattice atoms A are at the corner points and atoms B at the face centered points. If atom B is missing from one of the face centered points, the formula of the ionic compound is :

Choose one option
Answer and worked solution

Official answer: D

  • A at 8 corners: 8×18=18\times\frac18=1.
  • B at 5 of 6 faces: 5×12=525\times\frac12=\frac52.

ABX52\ce{AB_{5/2}}, i.e. AX2BX5\ce{A2B5}.