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← JEE Main 2014 · 6 Apr · Shift 1
PhysicsSingle correct+4 / -1Question 22 of 90

JEE Main 2014 · 6 Apr · Shift 1, Physics question 22

During the propagation of electromagnetic waves in a medium :

Choose one option
Answer and worked solution

Official answer: C

In an electromagnetic wave B=E/vB=E/v, so
uE=12ϵE2=12B2μ=uB.u_E=\tfrac12\epsilon E^2=\tfrac12\frac{B^2}{\mu}=u_B.
The electric and magnetic energy densities are equal.