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← JEE Main 2014 · 6 Apr · Shift 1
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JEE Main 2014 · 6 Apr · Shift 1, Physics question 20

The coercivity of a small magnet where the ferromagnet gets demagnetized is 3×1033\times10^3 A m−1^{-1}. The current required to be passed in a solenoid of length 10 cm and number of turns 100, so that the magnet gets demagnetized when inside the solenoid, is :

Choose one option
Answer and worked solution

Official answer: C

The solenoid's field intensity must reach the coercivity:
H=nI,n=1000.1=1000 m−1  ⟹  I=3×1031000=3 A.H=nI,\quad n=\frac{100}{0.1}=1000\text{ m}^{-1}\implies I=\frac{3\times10^3}{1000}=3\text{ A}.