JEE Main 2014 · 6 Apr · Shift 1 · Physics Q18

← JEE Main 2014 · 6 Apr · Shift 1

PhysicsSingle correct+4 / -1Question 18 of 90

In a large building, there are 15 bulbs of 40 W, 5 bulbs of 100 W, 5 fans of 80 W and 1 heater of 1 kW. The voltage of the electric mains is 220 V. The minimum capacity of the main fuse of the building will be :

8 A

10 A

12 A

14 A

Answer and worked solution

Official answer: C

Total power: $15(40)+5(100)+5(80)+1000=2500$ W.

Current: $I=\frac{2500}{220}=11.4$ A. The fuse must carry at least this, so the minimum standard capacity is 12 A.

Topics:Electrical power and heating

← Previous question Next question →

JEE Main 2014 · 6 Apr · Shift 1, Physics question 18