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JEE Main 2014 · 6 Apr · Shift 1, Physics question 16

Assume that an electric field E⃗=30x2 i^\vec E=30x^2\,\hat i exists in space. Then the potential difference VA−VOV_A-V_O, where VOV_O is the potential at the origin and VAV_A the potential at x=2x=2 m is :

Choose one option
Answer and worked solution

Official answer: C

VA−VO=−∫02E dx=−∫0230x2 dx=−10x3∣02=−80 V.V_A-V_O=-\int_0^2E\,dx=-\int_0^230x^2\,dx=-10x^3\Big|_0^2=-80\text{ V}.
(The options print the unit as J; the value is −80-80.)

Topics:Electric potentialElectric field
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