JEE Main 2014 · 6 Apr · Shift 1 · Physics Q1

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The current voltage relation of diode is given by $I=\left(e^{1000V/T}-1\right)$ mA, where the applied voltage $V$ is in volts and the temperature $T$ is in degree Kelvin. If a student makes an error measuring $\pm0.01$ V while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA ?

0.2 mA

0.02 mA

0.5 mA

0.05 mA

Answer and worked solution

Official answer: A

With $I+1=e^{1000V/T}$ mA, $\dfrac{dI}{dV}=\dfrac{1000}{T}e^{1000V/T}$ . At $I=5$ mA, $e^{1000V/T}=6$ , so
$\Delta I=\frac{1000}{300}\times6\times0.01=0.2\text{ mA}.$

Topics:Errors in measurement

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JEE Main 2014 · 6 Apr · Shift 1, Physics question 1