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JEE Main 2014 · 6 Apr · Shift 1, Mathematics question 85

If [a⃗×b⃗  b⃗×c⃗  c⃗×a⃗]=λ[a⃗ b⃗ c⃗]2\left[\vec a\times\vec b\ \ \vec b\times\vec c\ \ \vec c\times\vec a\right]=\lambda\left[\vec a\ \vec b\ \vec c\right]^2 then λ\lambda is equal to :

Choose one option
Answer and worked solution

Official answer: B

It is a standard identity that [a⃗×b⃗  b⃗×c⃗  c⃗×a⃗]=[a⃗ b⃗ c⃗]2\left[\vec a\times\vec b\ \ \vec b\times\vec c\ \ \vec c\times\vec a\right]=\left[\vec a\ \vec b\ \vec c\right]^2. So λ=1\lambda=1.

Topics:Scalar and vector triple products
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