JEE Main 2014 · 6 Apr · Shift 1 · Mathematics Q78

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MathematicsSingle correct+4 / -1Question 78 of 90

Let PS be the median of the triangle with vertices $P(2,2)$ , $Q(6,-1)$ and $R(7,3)$ . The equation of the line passing through $(1,-1)$ and parallel to PS is :

4x+7y+3=0

2x-9y-11=0

4x-7y-11=0

2x+9y+7=0

Answer and worked solution

Official answer: D

$S$ is the midpoint of $QR$ : $\left(\frac{13}2,1\right)$ . Slope of $PS$ : $\dfrac{1-2}{6.5-2}=-\dfrac29$ .

Through $(1,-1)$ : $y+1=-\frac29(x-1)$ , i.e. $2x+9y+7=0$ .

Topics:Equations of a line Distance and section formulae

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JEE Main 2014 · 6 Apr · Shift 1, Mathematics question 78