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← JEE Main 2014 · 6 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 60 of 90

JEE Main 2014 · 6 Apr · Shift 1, Chemistry question 60

In the reaction,
CHX3COOH→LiAlHX4A→PClX5B→Alc ⋅ KOHC,\ce{CH3COOH ->[LiAlH4] A ->[PCl5] B ->[Alc. KOH] C},
the product C is :

Choose one option
Answer and worked solution

Official answer: C

CHX3COOH→LiAlHX4CHX3CHX2OH→PClX5CHX3CHX2Cl→alc ⋅ KOHCHX2=CHX2.\ce{CH3COOH ->[LiAlH4] CH3CH2OH ->[PCl5] CH3CH2Cl ->[alc. KOH] CH2=CH2}.
C is ethylene.

Topics:AlcoholsElimination reactionsCarboxylic acids
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