JEE Main 2014 · 6 Apr · Shift 1 · Chemistry Q47

ChemistrySingle correct+4 / -1Question 47 of 90

The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. The ratio of number of their molecule is :

1 : 4

7 : 32

1 : 8

3 : 16

Answer and worked solution

Official answer: B

Take 1 g of $\ce{O2}$ and 4 g of $\ce{N2}$ :
$\frac{n_{\ce{O2}}}{n_{\ce{N2}}}=\frac{1/32}{4/28}=\frac{28}{128}=\frac7{32}.$

JEE Main 2014 · 6 Apr · Shift 1, Chemistry question 47