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← JEE Main 2014 · 6 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 45 of 90

JEE Main 2014 · 6 Apr · Shift 1, Chemistry question 45

In which of the following reactions HX2OX2\ce{H2O2} acts as a reducing agent ?

(a) HX2OX2+2 HX++2 eX−→2 HX2O\ce{H2O2 + 2H+ + 2e- -> 2H2O}

(b) HX2OX2−2 eX−→OX2+2 HX+\ce{H2O2 - 2e- -> O2 + 2H+}

(c) HX2OX2+2 eX−→2 OHX−\ce{H2O2 + 2e- -> 2OH-}

(d) HX2OX2+2 OHX−−2 eX−→OX2+2 HX2O\ce{H2O2 + 2OH- - 2e- -> O2 + 2H2O}

Choose one option
Answer and worked solution

Official answer: D

A reducing agent loses electrons. In (b) and (d), HX2OX2\ce{H2O2} gives up 2e−2e^- and is oxidised to OX2\ce{O2}. In (a) and (c) it gains electrons, acting as an oxidising agent.

Topics:Oxidation number
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