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← JEE Advanced 2026 · Paper 2
MathematicsMultiple correct+4 / -1Question 6 of 54

JEE Advanced 2026 · Paper 2, Mathematics question 6

Let a,b,ca,b,c be positive integers in arithmetic progression such that the equation
ax2+bx+c=0ax^2+bx+c=0
has only integer solutions.

Then which of the following statements is (are) TRUE ?

Choose one or more options
Answer and worked solution

Official answer: A, B, C

Integer roots. If the roots r,sr,s are integers, r+s=−bar+s=-\frac ba and rs=cars=\frac ca are integers. Put b=mab=ma, c=nac=na; the AP condition a+c=2ba+c=2b gives n=2m−1n=2m-1.

Both roots are negative (all coefficients positive). With p=−rp=-r, q=−sq=-s:
p+q=m,pq=2m−1=2(p+q)−1  ⟹  (p−2)(q−2)=3.p+q=m,\quad pq=2m-1=2(p+q)-1\implies(p-2)(q-2)=3.
With p,q≥1p,q\ge1 this forces {p,q}={3,5}\{p,q\}=\{3,5\}. So m=8m=8, n=15n=15: b=8ab=8a, c=15ac=15a, and the roots are −3,−5-3,-5.

  • (A) c−b=7ac-b=7a. True.
  • (B) −3-3 and −5-5 are odd. True.
  • (C) c=15⇒a=1, b=8c=15\Rightarrow a=1,\ b=8, so ab=8ab=8. True.
  • (D) b=8⇒a=1b=8\Rightarrow a=1; the roots are −3,−5-3,-5, not 33. False.