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← JEE Advanced 2026 · Paper 2
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JEE Advanced 2026 · Paper 2, Chemistry question 10

Xa+\mathbf X^{a+} and Yb+\mathbf Y^{b+} are hydrogen-like species. The wavelength of light absorbed during the transition between the states with principal quantum numbers n=1n=1 and n=2n=2 of Xa+\mathbf X^{a+} is λ\lambda. The wavelength of light absorbed during the transition between the states with principal quantum numbers n=2n=2 and n=4n=4 of Yb+\mathbf Y^{b+} is 9λ9\lambda. The lowest possible value of (a+b)(\boldsymbol a+\boldsymbol b) is ____.

Answer and worked solution

Official answer: 3

For a hydrogen-like ion, 1λ∝Z2(1n12−1n22)\dfrac1\lambda\propto Z^2\left(\dfrac1{n_1^2}-\dfrac1{n_2^2}\right).

  • X (1→21\to2): 1λ∝34ZX2\dfrac1\lambda\propto\dfrac34Z_X^2.
  • Y (2→42\to4): 19λ∝316ZY2\dfrac1{9\lambda}\propto\dfrac3{16}Z_Y^2.

Dividing,
9=34ZX2316ZY2=4ZX2ZY2  ⟹  ZYZX=23.9=\frac{\frac34Z_X^2}{\frac3{16}Z_Y^2}=\frac{4Z_X^2}{Z_Y^2}\implies\frac{Z_Y}{Z_X}=\frac23.

The smallest integers are ZX=3Z_X=3 (LiX2+\ce{Li^2+}, a=2a=2) and ZY=2Z_Y=2 (HeX+\ce{He+}, b=1b=1). So a+b=3a+b=3.