JEE Advanced 2026 · Paper 2 · Chemistry Q2

ChemistrySingle correct+3 / -1Question 38 of 54

The correct order of ONO bond angle in the given species is

\ce{NO2+}<\ce{NO2}<\ce{NO3-}<\ce{NO2-}

\ce{NO2-}<\ce{NO3-}<\ce{NO2}<\ce{NO2+}

\ce{NO3-}<\ce{NO2-}<\ce{NO2}<\ce{NO2+}

\ce{NO2-}<\ce{NO3-}<\ce{NO2+}<\ce{NO2}

Answer and worked solution

Official answer: B

$\ce{NO2+}$ : no lone pair on N, linear, $180^\circ$ .
$\ce{NO2}$ : one unpaired electron on N, which repels less than a lone pair, about $134^\circ$ .
$\ce{NO3-}$ : trigonal planar, $120^\circ$ .
$\ce{NO2-}$ : a full lone pair on N, about $115^\circ$ .

$\ce{NO2-}<\ce{NO3-}<\ce{NO2}<\ce{NO2+}.$

JEE Advanced 2026 · Paper 2, Chemistry question 2