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← JEE Advanced 2026 · Paper 1
MathematicsMultiple correct+4 / -1Question 8 of 48

JEE Advanced 2026 · Paper 1, Mathematics question 8

Consider the matrix
M=[2−110].M=\begin{bmatrix}2&-1\\1&0\end{bmatrix}.
Let p,q,r,s,a,b,cp,q,r,s,a,b,c and dd be integers such that
M26=[pqrs]and∑k=126Mk=[abcd].M^{26}=\begin{bmatrix}p&q\\r&s\end{bmatrix}\quad\text{and}\quad\sum_{k=1}^{26}M^k=\begin{bmatrix}a&b\\c&d\end{bmatrix}.
Then which of the following statements is (are) TRUE ?

Choose one or more options
Answer and worked solution

Official answer: A, C, D

Structure of MM. Write M=I+NM=I+N with N=[1−11−1]N=\begin{bmatrix}1&-1\\1&-1\end{bmatrix}. Then N2=0N^2=0, so
Mk=I+kN=[1+k−kk1−k].M^k=I+kN=\begin{bmatrix}1+k&-k\\k&1-k\end{bmatrix}.

(A) MM has the single eigenvalue 1 (characteristic polynomial (λ−1)2(\lambda-1)^2) and M≠IM\ne I, so it is similar to the Jordan block [1101]\begin{bmatrix}1&1\\0&1\end{bmatrix}. True.

(B) ∑k=126Mk=26I+(∑k)N=26I+351N\sum_{k=1}^{26}M^k=26I+\left(\sum k\right)N=26I+351N, so a=26+351=377a=26+351=377. False.

(C) M26=[27−2626−25]M^{26}=\begin{bmatrix}27&-26\\26&-25\end{bmatrix} has determinant 11, so its inverse has integer entries and the system has exactly one integer solution for any integers m,nm,n. True.

(D) The coefficient matrix is (26+t)I+351N(26+t)I+351N. Since NN is nilpotent, its determinant is (26+t)2>0(26+t)^2>0 for t>0t>0. True.