JEE Advanced 2026 · Paper 1 · Chemistry Q10

ChemistryNumerical+4Question 42 of 48

The total number of all possible isomers for the square planar complex with formula $\ce{K[M(NCS)(NO2)(gly)]}$ is ____.

(M = metal ion and gly = $\ce{NH2CH2COO-}$ )

Your answer

Answer and worked solution

Official answer: 8

$\ce{[M(NCS)(NO2)(gly)]-}$ is square planar of type $\ce{[M(AB)cd]}$ .

Geometric isomers: 2. The unsymmetrical glycinate (N and O donors) has NCS trans to N in one isomer and trans to O in the other.
Linkage isomers: ×2 for each ambidentate ligand. NCS can bind through N or S; $\ce{NO2}$ through N or O.

Total $2\times2\times2=8$ . (A square planar complex has no optical isomers.)

JEE Advanced 2026 · Paper 1, Chemistry question 10