JEE Advanced 2025 · Paper 1 · Chemistry Q14 · Dronacharya Exams

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ChemistryList match+4 / -1Question 46 of 48

The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is

List-I

P
Passing $\ce{H2S}$ in the presence of $\ce{NH4OH}$
Q
$\ce{(NH4)2CO3}$ in the presence of $\ce{NH4OH}$
R
$\ce{NH4OH}$ in the presence of $\ce{NH4Cl}$
S
Passing $\ce{H2S}$ in the presence of dilute HCl

List-II

1
$\ce{Cu^2+}$
2
$\ce{Al^3+}$
3
$\ce{Mn^2+}$
4
$\ce{Ba^2+}$
5
$\ce{Mg^2+}$

A

P → 3; Q → 4; R → 2; S → 1

B

P → 4; Q → 2; R → 3; S → 1

C

P → 3; Q → 4; R → 1; S → 5

D

P → 5; Q → 3; R → 2; S → 4

Answer and worked solution

Official answer: A

(P) $\ce{H2S}$ in the presence of $\ce{NH4OH}$ is the group IV reagent → $\ce{MnS}$ → (3).
(Q) $\ce{(NH4)2CO3}$ in the presence of $\ce{NH4OH}$ is the group V reagent → $\ce{BaCO3}$ → (4).
(R) $\ce{NH4OH}$ in the presence of $\ce{NH4Cl}$ is the group III reagent → $\ce{Al(OH)3}$ → (2).
(S) $\ce{H2S}$ in dilute HCl is the group II reagent → $\ce{CuS}$ → (1).

The match is P→3, Q→4, R→2, S→1, which is option (A).

Topics:Cation analysis

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