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← JEE Advanced 2024 · Paper 2
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JEE Advanced 2024 · Paper 2, Physics question 8

The dimensions of a cone are measured using a scale with a least count of 2 mm2\,\mathrm{mm}. The diameter of the base and the height are both measured to be 20.0 cm20.0\,\mathrm{cm}. The maximum percentage error in the determination of the volume is _____.

Answer and worked solution

Official answer: 3

V=13πr2h=πd2h12V=\frac13\pi r^2h=\frac{\pi d^2h}{12}. The maximum relative error is
ΔVV=2Δdd+Δhh=2⋅0.220+0.220=0.03,\frac{\Delta V}{V}=2\frac{\Delta d}{d}+\frac{\Delta h}{h}=2\cdot\frac{0.2}{20}+\frac{0.2}{20}=0.03,
i.e. 3%3\%.