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← JEE Advanced 2024 · Paper 2
ChemistryInteger+4Question 45 of 51

JEE Advanced 2024 · Paper 2, Chemistry question 11

A sample initially contains only U-238 isotope of uranium. With time, some of the U-238 radioactively decays into Pb-206 while the rest of it remains undisintegrated.

When the age of the sample is P×108\mathbf{P}\times10^8 years, the ratio of mass of Pb-206 to that of U-238 in the sample is found to be 7. The value of P is _____.

[Given: Half-life of U-238 is 4.5×1094.5\times10^9 years; log⁡e2=0.693\log_e 2 = 0.693]

Answer and worked solution

Official answer: Bonus: full marks to everyone

This question was dropped by the examiners, and marks were given to all. The working below shows why no single integer works.

Convert to a mole ratio. A mass ratio mPb/mU=7m_{Pb}/m_U=7 corresponds to
NPbNU=7⋅238206=8.09.\frac{N_{Pb}}{N_U}=7\cdot\frac{238}{206}=8.09.
So N0NU=1+8.09=9.09\dfrac{N_0}{N_U}=1+8.09=9.09.

Age.
t=t1/2ln⁡2ln⁡N0N=4.5×1090.693×ln⁡9.09≈6.49×109×2.207≈1.43×1010 yr,t=\frac{t_{1/2}}{\ln2}\ln\frac{N_0}{N}=\frac{4.5\times10^9}{0.693}\times\ln9.09\approx6.49\times10^9\times2.207\approx1.43\times10^{10}\ \text{yr},
so P≈143\mathbf P\approx143.

That is not an integer. If the ratio is read as an atom ratio instead (N0/N=8N_0/N=8, three half-lives), P=135\mathbf P=135. The ambiguity is why the question was dropped.