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ChemistryInteger+4Question 43 of 51

JEE Advanced 2024 · Paper 2, Chemistry question 9

Vessel-1 contains w2\mathbf{w_2} g of a non-volatile solute X dissolved in w1\mathbf{w_1} g of water. Vessel-2 contains w2\mathbf{w_2} g of another non-volatile solute Y dissolved in w1\mathbf{w_1} g of water. Both the vessels are at the same temperature and pressure. The molar mass of X is 80% of that of Y. The van't Hoff factor for X is 1.2 times of that of Y for their respective concentrations.

The elevation of boiling point for solution in Vessel-1 is _____ % of the solution in Vessel-2.

Answer and worked solution

Official answer: 150

ΔTb=iKb w2/Mw1/1000\Delta T_b=iK_b\,\dfrac{w_2/M}{w_1/1000}.

With w1w_1, w2w_2 and KbK_b the same in both vessels:
ΔTb(1)ΔTb(2)=iXiY⋅MYMX=1.2×10.8=1.5,\frac{\Delta T_b(1)}{\Delta T_b(2)}=\frac{i_X}{i_Y}\cdot\frac{M_Y}{M_X}=1.2\times\frac{1}{0.8}=1.5,
i.e. 150%150\%.

Topics:Colligative propertiesvan't Hoff factor
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