JEE Advanced 2024 · Paper 1 · Chemistry Q7

ChemistryMultiple correct+4 / -2Question 41 of 51

The option(s) in which at least three molecules follow Octet Rule is(are)

\ce{CO2}

\ce{C2H4}

\ce{NO}

and

\ce{HCl}

\ce{NO2}

\ce{O3}

\ce{HCl}

and

\ce{H2SO4}

\ce{BCl3}

\ce{NO}

\ce{NO2}

and

\ce{H2SO4}

\ce{CO2}

\ce{BCl3}

\ce{O3}

and

\ce{C2H4}

Answer and worked solution

Official answer: A, D

Octet obeyed: $\ce{CO2}$ , $\ce{C2H4}$ , $\ce{HCl}$ , $\ce{O3}$ .
Octet violated: $\ce{NO}$ and $\ce{NO2}$ (odd electron), $\ce{BCl3}$ (6 electrons on B), $\ce{H2SO4}$ (expanded octet on S in its usual structure).

JEE Advanced 2024 · Paper 1, Chemistry question 7