JEE Advanced 2024 · Paper 1 · Chemistry Q4

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ChemistrySingle correct+3 / -1Question 38 of 51

Among the following options, select the option in which each complex in Set-I shows geometrical isomerism and the two complexes in Set-II are ionization isomers of each other.

[en = $\ce{H2NCH2CH2NH2}$ ]

Set-I:

\ce{[Ni(CO)4]}

and

\ce{[PdCl2(PPh3)2]}

Set-II:

\ce{[Co(NH3)5Cl]SO4}

and

\ce{[Co(NH3)5(SO4)]Cl}

Set-I:

\ce{[Co(en)(NH3)2Cl2]}

and

\ce{[PdCl2(PPh3)2]}

Set-II:

\ce{[Co(NH3)6][Cr(CN)6]}

and

\ce{[Cr(NH3)6][Co(CN)6]}

Set-I:

\ce{[Co(NH3)3(NO2)3]}

and

\ce{[Co(en)2Cl2]}

Set-II:

\ce{[Co(NH3)5Cl]SO4}

and

\ce{[Co(NH3)5(SO4)]Cl}

Set-I:

\ce{[Cr(NH3)5Cl]Cl2}

and

\ce{[Co(en)(NH3)2Cl2]}

Set-II:

\ce{[Cr(H2O)6]Cl3}

and

\ce{[Cr(H2O)5Cl]Cl2.H2O}

Answer and worked solution

Official answer: C

Set-I (geometrical isomerism):

$\ce{[Ni(CO)4]}$ is tetrahedral (none), so (A) fails.
$\ce{[Cr(NH3)5Cl]Cl2}$ is $\ce{MA5B}$ (none), so (D) fails.
$\ce{[Co(NH3)3(NO2)3]}$ (fac/mer) and $\ce{[Co(en)2Cl2]}$ (cis/trans) both show it.

Set-II (ionization isomers, i.e. exchange of a ligand with a counter-ion):

$\ce{[Co(NH3)5Cl]SO4}$ / $\ce{[Co(NH3)5(SO4)]Cl}$ are ionization isomers ✓.
In (B), $\ce{[Co(NH3)6][Cr(CN)6]}$ / $\ce{[Cr(NH3)6][Co(CN)6]}$ are coordination isomers.

Answer: (C).

Topics:Isomerism in complexes

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