JEE Advanced 2024 · Paper 1 · Chemistry Q2

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ChemistrySingle correct+3 / -1Question 36 of 51

At room temperature, disproportionation of an aqueous solution of in situ generated nitrous acid ( $\ce{HNO2}$ ) gives the species

\ce{H3O+}

\ce{NO3-}

and

\ce{NO}

\ce{H3O+}

\ce{NO3-}

and

\ce{NO2}

\ce{H3O+}

\ce{NO-}

and

\ce{NO2}

\ce{H3O+}

\ce{NO3-}

and

\ce{N2O}

Answer and worked solution

Official answer: A

Nitrous acid disproportionates (N goes from +3 to +5 and +2):
$\ce{3HNO2 -> HNO3 + 2NO + H2O}$
In water, $\ce{HNO3}$ ionises to $\ce{H3O+}$ and $\ce{NO3-}$ . The species formed are $\ce{H3O+}$ , $\ce{NO3-}$ and $\ce{NO}$ .

Topics:Group 15 Oxidation number

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