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← JEE Advanced 2023 · Paper 2
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JEE Advanced 2023 · Paper 2, Mathematics question 2

Consider an experiment of tossing a coin repeatedly until the outcomes of two consecutive tosses are same. If the probability of a random toss resulting in head is 13\dfrac13, then the probability that the experiment stops with head is

Choose one option
Answer and worked solution

Official answer: B

Let p=13p=\frac13 (head) and q=23q=\frac23 (tail).

Shape of a run ending in heads. The experiment stops with head exactly when the tosses alternate and then end in HH. Before the final H there is an alternating string ending in H:
H, TH, HTH, THTH, …H,\ TH,\ HTH,\ THTH,\ \dots
Their probabilities are p, qp, p2q, p2q2,…p,\ qp,\ p^2q,\ p^2q^2,\dots

Sum.
∑=p(1+q)(1+pq+(pq)2+⋯ )=p(1+q)1−pq.\sum=p(1+q)\left(1+pq+(pq)^2+\cdots\right)=\frac{p(1+q)}{1-pq}.

Answer. Multiply by the final pp:
P=p2(1+q)1−pq=19⋅5379=521.P=\frac{p^2(1+q)}{1-pq}=\frac{\frac19\cdot\frac53}{\frac79}=\frac{5}{21}.