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← JEE Advanced 2023 · Paper 1
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JEE Advanced 2023 · Paper 1, Physics question 10

In an experiment for determination of the focal length of a thin convex lens, the distance of the object from the lens is 10±0.110 \pm 0.1 cm and the distance of its real image from the lens is 20±0.220 \pm 0.2 cm. The error in the determination of focal length of the lens is nn %. The value of nn is _____.

Answer and worked solution

Official answer: 1

Focal length. For a real image (magnitudes), 1f=1u+1v\dfrac1f=\dfrac1u+\dfrac1v:
f=10×2030=203 cm.f=\frac{10\times20}{30}=\frac{20}{3}\ \text{cm}.

Error. Differentiating:
Δff2=Δuu2+Δvv2=0.1100+0.2400=0.0015.\frac{\Delta f}{f^2}=\frac{\Delta u}{u^2}+\frac{\Delta v}{v^2}=\frac{0.1}{100}+\frac{0.2}{400}=0.0015.

Δff=0.0015×203=0.01=1%.\frac{\Delta f}{f}=0.0015\times\frac{20}{3}=0.01=1\%.