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← JEE Advanced 2023 · Paper 1
ChemistryList match+3 / -1Question 51 of 51

JEE Advanced 2023 · Paper 1, Chemistry question 17

The major products obtained from the reactions in List-II are the reactants for the named reactions mentioned in List-I. Match List-I with List-II and choose the correct option.

List-I

  • P
    Etard reaction
  • Q
    Gattermann reaction
  • R
    Gattermann-Koch reaction
  • S
    Rosenmund reduction

List-II

  • 1
    Acetophenone →Zn-Hg, HCl\xrightarrow{\text{Zn-Hg, HCl}}
  • 2
    Toluene →(ii) SOClX2(i) KMnOX4, KOH, Δ\xrightarrow[\text{(ii) } \ce{SOCl2}]{\text{(i) } \ce{KMnO4}\text{, KOH, }\Delta}
  • 3
    Benzene →anhyd. AlClX3CHX3Cl\xrightarrow[\text{anhyd. } \ce{AlCl3}]{\ce{CH3Cl}}
  • 4
    Aniline →273-278 KNaNOX2/HCl\xrightarrow[\text{273-278 K}]{\ce{NaNO2}/\ce{HCl}}
  • 5
    Phenol →Zn, Δ\xrightarrow{\text{Zn, }\Delta}
Choose one option
Answer and worked solution

Official answer: D

Products of the List-II reactions.

  1. Clemmensen reduction of acetophenone gives ethylbenzene.
  2. Toluene → benzoic acid → benzoyl chloride.
  3. Friedel-Crafts methylation of benzene gives toluene.
  4. Diazotisation of aniline gives benzenediazonium chloride.
  5. Zinc dust converts phenol to benzene.

Matching each named reaction to its reactant.

  • Etard reaction: toluene with CrOX2ClX2\ce{CrO2Cl2} → 3.
  • Gattermann reaction: a diazonium salt with Cu/HX → 4.
  • Gattermann-Koch reaction: benzene with CO/HCl → 5.
  • Rosenmund reduction: an acid chloride → 2.

P→3, Q→4, R→5, S→2.