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← JEE Advanced 2023 · Paper 1
ChemistryList match+3 / -1Question 49 of 51

JEE Advanced 2023 · Paper 1, Chemistry question 15

Match the electronic configurations in List-I with appropriate metal complex ions in List-II and choose the correct option.

[Atomic Number: Fe = 26, Mn = 25, Co = 27]

List-I

  • P
    t2g6 eg0t_{2g}^6\,e_g^0
  • Q
    t2g3 eg2t_{2g}^3\,e_g^2
  • R
    e2 t23e^2\,t_2^3
  • S
    t2g4 eg2t_{2g}^4\,e_g^2

List-II

  • 1
    [Fe(HX2O)X6]X2+\ce{[Fe(H2O)6]^2+}
  • 2
    [Mn(HX2O)X6]X2+\ce{[Mn(H2O)6]^2+}
  • 3
    [Co(NHX3)X6]X3+\ce{[Co(NH3)6]^3+}
  • 4
    [FeClX4]X−\ce{[FeCl4]-}
  • 5
    [CoClX4]X2−\ce{[CoCl4]^2-}
Choose one option
Answer and worked solution

Official answer: D

Complex Metal ion Field Configuration
[Fe(HX2O)X6]X2+\ce{[Fe(H2O)6]^2+} Fe(II) d6d^6 weak, octahedral t2g4eg2t_{2g}^4e_g^2
[Mn(HX2O)X6]X2+\ce{[Mn(H2O)6]^2+} Mn(II) d5d^5 weak, octahedral t2g3eg2t_{2g}^3e_g^2
[Co(NHX3)X6]X3+\ce{[Co(NH3)6]^3+} Co(III) d6d^6 strong, octahedral t2g6eg0t_{2g}^6e_g^0
[FeClX4]X−\ce{[FeCl4]-} Fe(III) d5d^5 tetrahedral e2t23e^2t_2^3
[CoClX4]X2−\ce{[CoCl4]^2-} Co(II) d7d^7 tetrahedral e4t23e^4t_2^3

P→3, Q→2, R→4, S→1.