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← JEE Advanced 2022 · Paper 2
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JEE Advanced 2022 · Paper 2, Physics question 11

A bubble has surface tension SS. The ideal gas inside the bubble has ratio of specific heats γ=53\gamma = \dfrac53. The bubble is exposed to the atmosphere and it always retains its spherical shape. When the atmospheric pressure is Pa1P_{a1}, the radius of the bubble is found to be r1r_1 and the temperature of the enclosed gas is T1T_1. When the atmospheric pressure is Pa2P_{a2}, the radius of the bubble and the temperature of the enclosed gas are r2r_2 and T2T_2, respectively.

Which of the following statement(s) is(are) correct?

Choose one or more options
Answer and worked solution

Official answer: C, D

Gas pressure. A bubble has two surfaces, so the gas pressure is P=Pa+4SrP=P_a+\frac{4S}r, and the volume is proportional to r3r^3.

Insulating surface (adiabatic).

  • PVγPV^\gamma is constant with 3γ=53\gamma=5, so (r1r2)5=Pa2+4S/r2Pa1+4S/r1\left(\dfrac{r_1}{r_2}\right)^5=\dfrac{P_{a2}+4S/r_2}{P_{a1}+4S/r_1}. Option (A) uses 2S/r2S/r, so it is false.
  • TγP1−γT^\gamma P^{1-\gamma} is constant, so P∝Tγ/(γ−1)=T5/2P\propto T^{\gamma/(\gamma-1)}=T^{5/2}. This gives (D). True.
  • The atmosphere does work on the bubble when PaP_a changes, so the total energy, surface energy included, changes. (B) is false.

Conducting surface, constant temperature. PVPV is constant, so
(r1r2)3=Pa2+4S/r2Pa1+4S/r1.\left(\frac{r_1}{r_2}\right)^3=\frac{P_{a2}+4S/r_2}{P_{a1}+4S/r_1}.
(C) is true.

(C), (D).